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1/2x+3/2(x+1)=5
We move all terms to the left:
1/2x+3/2(x+1)-(5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2(x+1)!=0We calculate fractions
x∈R
(2xx/(4x^2x+6x/(4x^2x-5=0
We can not solve this equation
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