2(3x-4)+x-1=16

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Solution for 2(3x-4)+x-1=16 equation: 



2(3x-4)+x-1=16

We move all terms to the left:

2(3x-4)+x-1-(16)=0

We add all the numbers together, and all the variables

x+2(3x-4)-17=0

We multiply parentheses

x+6x-8-17=0

We add all the numbers together, and all the variables

7x-25=0

We move all terms containing x to the left, all other terms to the right

7x=25

x=25/7

x=3+4/7

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