1/2x+2/3=1/3x-12

Solution for 1/2x+2/3=1/3x-12 equation:

1/2x+2/3=1/3x-12

We move all terms to the left:

1/2x+2/3-(1/3x-12)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x-12)!=0

x∈R


We get rid of parentheses

1/2x-1/3x+12+2/3=0

We calculate fractions


27x/54x^2+(-2x)/54x^2+4x/54x^2+12=0

We multiply all the terms by the denominator


27x+(-2x)+4x+12*54x^2=0

We add all the numbers together, and all the variables

31x+(-2x)+12*54x^2=0

Wy multiply elements

648x^2+31x+(-2x)=0

We get rid of parentheses

648x^2+31x-2x=0

We add all the numbers together, and all the variables

648x^2+29x=0

a = 648; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·648·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*648}=\frac{-58}{1296}
=-29/648
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*648}=\frac{0}{1296}
=0
$