3y-6+2(5y+2)=-3(y+4)

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Solution for 3y-6+2(5y+2)=-3(y+4) equation: 



3y-6+2(5y+2)=-3(y+4)

We move all terms to the left:

3y-6+2(5y+2)-(-3(y+4))=0

We multiply parentheses

3y+10y-(-3(y+4))+4-6=0



We calculate terms in parentheses: -(-3(y+4)), so:

-3(y+4)

We multiply parentheses

-3y-12

Back to the equation:

-(-3y-12)



We add all the numbers together, and all the variables

13y-(-3y-12)-2=0

We get rid of parentheses

13y+3y+12-2=0

We add all the numbers together, and all the variables

16y+10=0

We move all terms containing y to the left, all other terms to the right

16y=-10

y=-10/16

y=-5/8

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