1/2x+16=3/8x+4

Solution for 1/2x+16=3/8x+4 equation:

1/2x+16=3/8x+4

We move all terms to the left:

1/2x+16-(3/8x+4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 8x+4)!=0

x∈R


We get rid of parentheses

1/2x-3/8x-4+16=0

We calculate fractions


8x/16x^2+(-6x)/16x^2-4+16=0

We add all the numbers together, and all the variables

8x/16x^2+(-6x)/16x^2+12=0

We multiply all the terms by the denominator


8x+(-6x)+12*16x^2=0

Wy multiply elements

192x^2+8x+(-6x)=0

We get rid of parentheses

192x^2+8x-6x=0

We add all the numbers together, and all the variables

192x^2+2x=0

a = 192; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·192·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*192}=\frac{-4}{384}
=-1/96
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*192}=\frac{0}{384}
=0
$