8(y-2)=12(y+3)

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Solution for 8(y-2)=12(y+3) equation: 



8(y-2)=12(y+3)

We move all terms to the left:

8(y-2)-(12(y+3))=0

We multiply parentheses

8y-(12(y+3))-16=0



We calculate terms in parentheses: -(12(y+3)), so:

12(y+3)

We multiply parentheses

12y+36

Back to the equation:

-(12y+36)



We get rid of parentheses

8y-12y-36-16=0

We add all the numbers together, and all the variables

-4y-52=0

We move all terms containing y to the left, all other terms to the right

-4y=52

y=52/-4

y=-13

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