1/2x+1/3=1/6x-5

Solution for 1/2x+1/3=1/6x-5 equation:

1/2x+1/3=1/6x-5

We move all terms to the left:

1/2x+1/3-(1/6x-5)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 6x-5)!=0

x∈R


We get rid of parentheses

1/2x-1/6x+5+1/3=0

We calculate fractions


72x^2/108x^2+54x/108x^2+(-18x)/108x^2+5=0

We multiply all the terms by the denominator


72x^2+54x+(-18x)+5*108x^2=0

Wy multiply elements

72x^2+540x^2+54x+(-18x)=0

We get rid of parentheses

72x^2+540x^2+54x-18x=0

We add all the numbers together, and all the variables

612x^2+36x=0

a = 612; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·612·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*612}=\frac{-72}{1224}
=-1/17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*612}=\frac{0}{1224}
=0
$