x2+8x=56

Solution for x2+8x=56 equation:

x2+8x=56

We move all terms to the left:

x2+8x-(56)=0

We add all the numbers together, and all the variables

x^2+8x-56=0

a = 1; b = 8; c = -56;
Δ = b2-4ac
Δ = 82-4·1·(-56)
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-12\sqrt{2}}{2*1}=\frac{-8-12\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+12\sqrt{2}}{2*1}=\frac{-8+12\sqrt{2}}{2}
$