1/2x(4-8x)=-3(8x-4)

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Solution for 1/2x(4-8x)=-3(8x-4) equation: 



1/2x(4-8x)=-3(8x-4)

We move all terms to the left:

1/2x(4-8x)-(-3(8x-4))=0



Domain of the equation: 2x(4-8x)!=0

x∈R



We add all the numbers together, and all the variables

1/2x(-8x+4)-(-3(8x-4))=0

We multiply all the terms by the denominator


-((-3(8x-4)))*2x(-8x+4)+1=0



We calculate terms in parentheses: -((-3(8x-4)))*2x(-8x+4), so:

(-3(8x-4)))*2x(-8x+4

We add all the numbers together, and all the variables

-8x+(-3(8x-4)))*2x(+4

Back to the equation:

-(-8x+(-3(8x-4)))*2x(+4)



We add all the numbers together, and all the variables

-(-8x+(-3(8x-4)))*2x4+1=0

We move all terms containing x to the left, all other terms to the right

-(-8x+(-3(8x-4)))*2x4=-1

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