1/2c-3/3c=4

Solution for 1/2c-3/3c=4 equation:

1/2c-3/3c=4

We move all terms to the left:

1/2c-3/3c-(4)=0


Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R


We calculate fractions


3c/6c^2+(-6c)/6c^2-4=0

We multiply all the terms by the denominator


3c+(-6c)-4*6c^2=0

Wy multiply elements

-24c^2+3c+(-6c)=0

We get rid of parentheses

-24c^2+3c-6c=0

We add all the numbers together, and all the variables

-24c^2-3c=0

a = -24; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-24)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-24}=\frac{0}{-48}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-24}=\frac{6}{-48}
=-1/8
$