1/2(z+12)=3/2(z+6)

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Solution for 1/2(z+12)=3/2(z+6) equation: 



1/2(z+12)=3/2(z+6)

We move all terms to the left:

1/2(z+12)-(3/2(z+6))=0



Domain of the equation: 2(z+12)!=0

z∈R





Domain of the equation: 2(z+6))!=0

z∈R



We calculate fractions


(2zz/(2(z+12)*2(z+6)))+(-6zz/(2(z+12)*2(z+6)))=0



We calculate terms in parentheses: +(2zz/(2(z+12)*2(z+6))), so:

2zz/(2(z+12)*2(z+6))

We multiply all the terms by the denominator


2zz

Back to the equation:

+(2zz)





We calculate terms in parentheses: +(-6zz/(2(z+12)*2(z+6))), so:

-6zz/(2(z+12)*2(z+6))

We multiply all the terms by the denominator


-6zz

Back to the equation:

+(-6zz)



We get rid of parentheses

2zz-6zz=0

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