8x(5x-1)=180

Solution for 8x(5x-1)=180 equation:

8x(5x-1)=180

We move all terms to the left:

8x(5x-1)-(180)=0

We multiply parentheses

40x^2-8x-180=0

a = 40; b = -8; c = -180;
Δ = b2-4ac
Δ = -82-4·40·(-180)
Δ = 28864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28864}=\sqrt{64*451}=\sqrt{64}*\sqrt{451}=8\sqrt{451}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8\sqrt{451}}{2*40}=\frac{8-8\sqrt{451}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8\sqrt{451}}{2*40}=\frac{8+8\sqrt{451}}{80}
$