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1/2(y-3)+2=3/4(5y-21)
We move all terms to the left:
1/2(y-3)+2-(3/4(5y-21))=0
Domain of the equation: 2(y-3)!=0
y∈R
Domain of the equation: 4(5y-21))!=0We calculate fractions
y∈R
(4y5/(2(y-3)*4(5y-21)))+(-6yy/(2(y-3)*4(5y-21)))+2=0
We calculate terms in parentheses: +(4y5/(2(y-3)*4(5y-21))), so:
4y5/(2(y-3)*4(5y-21))
We multiply all the terms by the denominator
4y5
We add all the numbers together, and all the variables
4y^5
We do not support eypression: y^5
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