1/2(x-1)+2x=1/3(2x+2)

Solution for 1/2(x-1)+2x=1/3(2x+2) equation:

1/2(x-1)+2x=1/3(2x+2)

We move all terms to the left:

1/2(x-1)+2x-(1/3(2x+2))=0


Domain of the equation: 2(x-1)!=0

x∈R



Domain of the equation: 3(2x+2))!=0

x∈R


We add all the numbers together, and all the variables

2x+1/2(x-1)-(1/3(2x+2))=0

We calculate fractions


2x+(3x2/(2(x-1)*3(2x+2)))+(-2xx/(2(x-1)*3(2x+2)))=0


We calculate terms in parentheses: +(3x2/(2(x-1)*3(2x+2))), so:

3x2/(2(x-1)*3(2x+2))

We multiply all the terms by the denominator


3x2

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)



We calculate terms in parentheses: +(-2xx/(2(x-1)*3(2x+2))), so:

-2xx/(2(x-1)*3(2x+2))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


determiningTheFunctionDomain
3x^2+2x+(-2xx)=0

We get rid of parentheses

3x^2+2x-2xx=0