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(x-3)*2=x*2-3(x+1)
We move all terms to the left:
(x-3)*2-(x*2-3(x+1))=0
We multiply parentheses
2x-(x*2-3(x+1))-6=0
We calculate terms in parentheses: -(x*2-3(x+1)), so:We get rid of parentheses
x*2-3(x+1)
We multiply parentheses
x*2-3x-3
Wy multiply elements
2x-3x-3
We add all the numbers together, and all the variables
-1x-3
Back to the equation:
-(-1x-3)
2x+1x+3-6=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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