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1/2(x+4)+1/3(x+9)-6=2(x+2
We move all terms to the left:
1/2(x+4)+1/3(x+9)-6-(2(x+2)=0
Domain of the equation: 2(x+4)!=0
x∈R
Domain of the equation: 3(x+9)!=0We calculate fractions
x∈R
-(2(x+2)-6+(3xx/(2(x+4)*3(x+9))+(2xx/(2(x+4)*3(x+9))=0
We calculate terms in parentheses: -(2(x+2)-6+(3xx/(2(x+4)*3(x+9))+(2xx/(2(x+4)*3(x+9)), so:
2(x+2)-6+(3xx/(2(x+4)*3(x+9))+(2xx/(2(x+4)*3(x+9)
We can not solve this equation
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