10x-2=1/2(27x+3-(9x-5)

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Solution for 10x-2=1/2(27x+3-(9x-5) equation: 



10x-2=1/2(27x+3-(9x-5)

We move all terms to the left:

10x-2-(1/2(27x+3-(9x-5))=0



Domain of the equation: 2(27x+3-(9x-5))-2!=0

We move all terms containing x to the left, all other terms to the right

2(27x+3-(9x-5))!=2

x∈R



We multiply all the terms by the denominator


10x*2(27x+3-(9x-5))-2-(1=0

We add all the numbers together, and all the variables

10x*2(27x+3-(9x-5))=0

Wy multiply elements

20x^2(2=0

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