1/2(x+4)+1/2(4x)+1/2(10x-10)=288

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Solution for 1/2(x+4)+1/2(4x)+1/2(10x-10)=288 equation: 



1/2(x+4)+1/2(4x)+1/2(10x-10)=288

We move all terms to the left:

1/2(x+4)+1/2(4x)+1/2(10x-10)-(288)=0



Domain of the equation: 2(x+4)!=0

x∈R





Domain of the equation: 24x!=0

x!=0/24

x!=0

x∈R





Domain of the equation: 2(10x-10)!=0

x∈R



We calculate fractions


96x^2/(2(x+4)*24x*2(10x-10))+(4x^2x/(2(x+4)*24x*2(10x-10))+(48x^2x/(2(x+4)*24x*2(10x-10))-288=0

We can not solve this equation

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