2(u-4)-3=-7(-2u+3)-4u

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Solution for 2(u-4)-3=-7(-2u+3)-4u equation: 



2(u-4)-3=-7(-2u+3)-4u

We move all terms to the left:

2(u-4)-3-(-7(-2u+3)-4u)=0

We multiply parentheses

2u-(-7(-2u+3)-4u)-8-3=0



We calculate terms in parentheses: -(-7(-2u+3)-4u), so:

-7(-2u+3)-4u

We add all the numbers together, and all the variables

-4u-7(-2u+3)

We multiply parentheses

-4u+14u-21

We add all the numbers together, and all the variables

10u-21

Back to the equation:

-(10u-21)



We add all the numbers together, and all the variables

2u-(10u-21)-11=0

We get rid of parentheses

2u-10u+21-11=0

We add all the numbers together, and all the variables

-8u+10=0

We move all terms containing u to the left, all other terms to the right

-8u=-10

u=-10/-8

u=1+1/4

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