1/2(x+22)=3(x+4)

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Solution for 1/2(x+22)=3(x+4) equation: 



1/2(x+22)=3(x+4)

We move all terms to the left:

1/2(x+22)-(3(x+4))=0



Domain of the equation: 2(x+22)!=0

x∈R



We multiply all the terms by the denominator


-((3(x+4)))*2(x+22)+1=0



We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), so:

(3(x+4)))*2(x+22





We calculate terms in parentheses: -((3(x+4)))*2(x+22), s

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