6(v+3)=-2(8v-4)+7v

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Solution for 6(v+3)=-2(8v-4)+7v equation: 



6(v+3)=-2(8v-4)+7v

We move all terms to the left:

6(v+3)-(-2(8v-4)+7v)=0

We multiply parentheses

6v-(-2(8v-4)+7v)+18=0



We calculate terms in parentheses: -(-2(8v-4)+7v), so:

-2(8v-4)+7v

We add all the numbers together, and all the variables

7v-2(8v-4)

We multiply parentheses

7v-16v+8

We add all the numbers together, and all the variables

-9v+8

Back to the equation:

-(-9v+8)



We get rid of parentheses

6v+9v-8+18=0

We add all the numbers together, and all the variables

15v+10=0

We move all terms containing v to the left, all other terms to the right

15v=-10

v=-10/15

v=-2/3

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