1/2(x+1)+1/3(x-1)=5/12(x-2)

Solution for 1/2(x+1)+1/3(x-1)=5/12(x-2) equation:

1/2(x+1)+1/3(x-1)=5/12(x-2)

We move all terms to the left:

1/2(x+1)+1/3(x-1)-(5/12(x-2))=0


Domain of the equation: 2(x+1)!=0

x∈R



Domain of the equation: 3(x-1)!=0

x∈R



Domain of the equation: 12(x-2))!=0

x∈R


We calculate fractions


(-30x^2x/(2(x+1)*3(x-1)*12(x-2)))+(36x^2x/(2(x+1)*3(x-1)*12(x-2)))+(24x^2x/(2(x+1)*3(x-1)*12(x-2)))=0


We calculate terms in parentheses: +(-30x^2x/(2(x+1)*3(x-1)*12(x-2))), so:

-30x^2x/(2(x+1)*3(x-1)*12(x-2))

We multiply all the terms by the denominator


-30x^2x

Back to the equation:

+(-30x^2x)



We calculate terms in parentheses: +(36x^2x/(2(x+1)*3(x-1)*12(x-2))), so:

36x^2x/(2(x+1)*3(x-1)*12(x-2))

We multiply all the terms by the denominator


36x^2x

Back to the equation:

+(36x^2x)



We calculate terms in parentheses: +(24x^2x/(2(x+1)*3(x-1)*12(x-2))), so:

24x^2x/(2(x+1)*3(x-1)*12(x-2))

We multiply all the terms by the denominator


24x^2x

Back to the equation:

+(24x^2x)


We get rid of parentheses

-30x^2x+36x^2x+24x^2x=0