(6y-6)+3(4y+1)=48

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Solution for (6y-6)+3(4y+1)=48 equation: 



(6y-6)+3(4y+1)=48

We move all terms to the left:

(6y-6)+3(4y+1)-(48)=0

We multiply parentheses

(6y-6)+12y+3-48=0

We get rid of parentheses

6y+12y-6+3-48=0

We add all the numbers together, and all the variables

18y-51=0

We move all terms containing y to the left, all other terms to the right

18y=51

y=51/18

y=2+5/6

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