6(3n+2)-5(6n-1)=3(n-8)-5(7n-6)+9n

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Solution for 6(3n+2)-5(6n-1)=3(n-8)-5(7n-6)+9n equation: 



6(3n+2)-5(6n-1)=3(n-8)-5(7n-6)+9n

We move all terms to the left:

6(3n+2)-5(6n-1)-(3(n-8)-5(7n-6)+9n)=0

We multiply parentheses

18n-30n-(3(n-8)-5(7n-6)+9n)+12+5=0



We calculate terms in parentheses: -(3(n-8)-5(7n-6)+9n), so:

3(n-8)-5(7n-6)+9n

We add all the numbers together, and all the variables

9n+3(n-8)-5(7n-6)

We multiply parentheses

9n+3n-35n-24+30

We add all the numbers together, and all the variables

-23n+6

Back to the equation:

-(-23n+6)



We add all the numbers together, and all the variables

-12n-(-23n+6)+17=0

We get rid of parentheses

-12n+23n-6+17=0

We add all the numbers together, and all the variables

11n+11=0

We move all terms containing n to the left, all other terms to the right

11n=-11

n=-11/11

n=-1

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