1/2(s+12)=1/4(s+16)

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Solution for 1/2(s+12)=1/4(s+16) equation: 



1/2(s+12)=1/4(s+16)

We move all terms to the left:

1/2(s+12)-(1/4(s+16))=0



Domain of the equation: 2(s+12)!=0

s∈R





Domain of the equation: 4(s+16))!=0

s∈R



We calculate fractions


(4ss/(2(s+12)*4(s+16)))+(-2ss/(2(s+12)*4(s+16)))=0



We calculate terms in parentheses: +(4ss/(2(s+12)*4(s+16))), so:

4ss/(2(s+12)*4(s+16))

We multiply all the terms by the denominator


4ss

Back to the equation:

+(4ss)





We calculate terms in parentheses: +(-2ss/(2(s+12)*4(s+16))), so:

-2ss/(2(s+12)*4(s+16))

We multiply all the terms by the denominator


-2ss

Back to the equation:

+(-2ss)



We get rid of parentheses

4ss-2ss=0

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