1/2(8y+10)=3(y-7)

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Solution for 1/2(8y+10)=3(y-7) equation:



1/2(8y+10)=3(y-7)
We move all terms to the left:
1/2(8y+10)-(3(y-7))=0
Domain of the equation: 2(8y+10)!=0
y∈R
We multiply all the terms by the denominator
-((3(y-7)))*2(8y+10)+1=0
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
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(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We calculate terms in parentheses: -((3(y-7)))*2(8y+10), so:
(3(y-7)))*2(8y+10
We move all terms containing y to the left, all other terms to the right
-((3(y-7)))*2(8y+10)=-1

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