1/2(8x-4)-20=16-4x+2

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Solution for 1/2(8x-4)-20=16-4x+2 equation: 



1/2(8x-4)-20=16-4x+2

We move all terms to the left:

1/2(8x-4)-20-(16-4x+2)=0



Domain of the equation: 2(8x-4)!=0

x∈R



We add all the numbers together, and all the variables

1/2(8x-4)-(-4x+18)-20=0

We get rid of parentheses

1/2(8x-4)+4x-18-20=0

We multiply all the terms by the denominator


4x*2(8x-4)-18*2(8x-4)-20*2(8x-4)+1=0

Wy multiply elements

8x^2(8-36x(8-40x(8+1=0

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