1/4(a+2)=1/5(7-a)

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Solution for 1/4(a+2)=1/5(7-a) equation: 



1/4(a+2)=1/5(7-a)

We move all terms to the left:

1/4(a+2)-(1/5(7-a))=0



Domain of the equation: 4(a+2)!=0

a∈R





Domain of the equation: 5(7-a))!=0

a∈R



We add all the numbers together, and all the variables

1/4(a+2)-(1/5(-1a+7))=0

We calculate fractions


(5a(-)/(4(a+2)*5(-1a+7)))+(-4aa/(4(a+2)*5(-1a+7)))=0



We calculate terms in parentheses: +(5a(-)/(4(a+2)*5(-1a+7))), so:

5a(-)/(4(a+2)*5(-1a+7))

We add all the numbers together, and all the variables

5a0/(4(a+2)*5(-1a+7))

We multiply all the terms by the denominator


5a0

We add all the numbers together, and all the variables

5a

Back to the equation:

+(5a)





We calculate terms in parentheses: +(-4aa/(4(a+2)*5(-1a+7))), so:

-4aa/(4(a+2)*5(-1a+7))

We multiply all the terms by the denominator


-4aa

Back to the equation:

+(-4aa)



We get rid of parentheses

5a-4aa=0

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