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1/2(8a-22)=2(a+a)
We move all terms to the left:
1/2(8a-22)-(2(a+a))=0
Domain of the equation: 2(8a-22)!=0We add all the numbers together, and all the variables
a∈R
1/2(8a-22)-(2(+2a))=0
We multiply all the terms by the denominator
-((2(+2a)))*2(8a-22)+1=0
We calculate terms in parentheses: -((2(+2a)))*2(8a-22), so:
(2(+2a)))*2(8a-22
We calculate terms in parentheses: -((2(+2a)))*2(8a-22), so:
(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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(2(+2a)))*2(8a-22
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