1/2(8a-22)=2(a+8)

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Solution for 1/2(8a-22)=2(a+8) equation: 



1/2(8a-22)=2(a+8)

We move all terms to the left:

1/2(8a-22)-(2(a+8))=0



Domain of the equation: 2(8a-22)!=0

a∈R



We multiply all the terms by the denominator


-((2(a+8)))*2(8a-22)+1=0



We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





We calculate terms in parentheses: -((2(a+8)))*2(8a-22), so:

(2(a+8)))*2(8a-22





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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