1/2(6x-8)-(x+5)=3+2(x+4)

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Solution for 1/2(6x-8)-(x+5)=3+2(x+4) equation: 



1/2(6x-8)-(x+5)=3+2(x+4)

We move all terms to the left:

1/2(6x-8)-(x+5)-(3+2(x+4))=0



Domain of the equation: 2(6x-8)!=0

x∈R



We get rid of parentheses

1/2(6x-8)-x-(3+2(x+4))-5=0

We multiply all the terms by the denominator


-x*2(6x-8)-((3+2(x+4)))*2(6x-8)-5*2(6x-8)+1=0



We calculate terms in parentheses: -((3+2(x+4)))*2(6x-8), so:

(3+2(x+4)))*2(6x-8



Wy multiply elements

-2x^2(6-((3+2(x+4)))*2(6x-8)-10x(6+1=0

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