1/2(6x-10)-x=1/3(13x-41)

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Solution for 1/2(6x-10)-x=1/3(13x-41) equation:



1/2(6x-10)-x=1/3(13x-41)
We move all terms to the left:
1/2(6x-10)-x-(1/3(13x-41))=0
Domain of the equation: 2(6x-10)!=0
x∈R
Domain of the equation: 3(13x-41))!=0
x∈R
We add all the numbers together, and all the variables
-1x+1/2(6x-10)-(1/3(13x-41))=0
We calculate fractions
-1x+(3x1/(2(6x-10)*3(13x-41)))+(-2x6/(2(6x-10)*3(13x-41)))=0
We calculate terms in parentheses: +(3x1/(2(6x-10)*3(13x-41))), so:
3x1/(2(6x-10)*3(13x-41))
We multiply all the terms by the denominator
3x1
We add all the numbers together, and all the variables
3x
Back to the equation:
+(3x)
We calculate terms in parentheses: +(-2x6/(2(6x-10)*3(13x-41))), so:
-2x6/(2(6x-10)*3(13x-41))
We multiply all the terms by the denominator
-2x6
We add all the numbers together, and all the variables
-2x^6
We do not support expression: x^6

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