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1/2(5z-3)=0.25(3z+2
We move all terms to the left:
1/2(5z-3)-(0.25(3z+2)=0
Domain of the equation: 2(5z-3)!=0We multiply all the terms by the denominator
z∈R
-((0.25(3z+2))*2(5z-3)+1=0
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