1/2(4x-8)-12=-1/4(8x+4

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Solution for 1/2(4x-8)-12=-1/4(8x+4 equation: 



1/2(4x-8)-12=-1/4(8x+4

We move all terms to the left:

1/2(4x-8)-12-(-1/4(8x+4)=0



Domain of the equation: 2(4x-8)!=0

x∈R





Domain of the equation: 4(8x+4)-12!=0

We move all terms containing x to the left, all other terms to the right

4(8x+4)!=12

x∈R



We calculate fractions


(4x(8-12)/(2(4x-8)*4(8x+4)-12)+(-(-2x4)/(2(4x-8)*4(8x+4)-12)=0



We calculate terms in parentheses: +(4x(8-12)/(2(4x-8)*4(8x+4)-12)+(-(-2x4)/(2(4x-8)*4(8x+4)-12), so:

4x(8-12)/(2(4x-8)*4(8x+4)-12)+(-(-2x4)/(2(4x-8)*4(8x+4)-12

We add all the numbers together, and all the variables

(-(-2x^4)/(2(4x-8)*4(8x+4)-12+4x(-4)/(2(4x-8)*4(8x+4)-12)

We can not solve this equation

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