4(2n+1)-3(2n+5)=29

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Solution for 4(2n+1)-3(2n+5)=29 equation: 



4(2n+1)-3(2n+5)=29

We move all terms to the left:

4(2n+1)-3(2n+5)-(29)=0

We multiply parentheses

8n-6n+4-15-29=0

We add all the numbers together, and all the variables

2n-40=0

We move all terms containing n to the left, all other terms to the right

2n=40

n=40/2

n=20

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