1/2(4x-2)=7+x

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Solution for 1/2(4x-2)=7+x equation: 



1/2(4x-2)=7+x

We move all terms to the left:

1/2(4x-2)-(7+x)=0



Domain of the equation: 2(4x-2)!=0

x∈R



We add all the numbers together, and all the variables

1/2(4x-2)-(x+7)=0

We get rid of parentheses

1/2(4x-2)-x-7=0

We multiply all the terms by the denominator


-x*2(4x-2)-7*2(4x-2)+1=0

Wy multiply elements

-2x^2(4-14x(4+1=0

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