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3(1-x)=2(2-2x)
We move all terms to the left:
3(1-x)-(2(2-2x))=0
We add all the numbers together, and all the variables
3(-1x+1)-(2(-2x+2))=0
We multiply parentheses
-3x-(2(-2x+2))+3=0
We calculate terms in parentheses: -(2(-2x+2)), so:We get rid of parentheses
2(-2x+2)
We multiply parentheses
-4x+4
Back to the equation:
-(-4x+4)
-3x+4x-4+3=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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