1/2(4x-10)-x/2=1/5(x+14)

Solution for 1/2(4x-10)-x/2=1/5(x+14) equation:

1/2(4x-10)-x/2=1/5(x+14)

We move all terms to the left:

1/2(4x-10)-x/2-(1/5(x+14))=0


Domain of the equation: 2(4x-10)!=0

x∈R



Domain of the equation: 5(x+14))!=0

x∈R


We calculate fractions


(-5x^2x/(2(4x-10)*2*5(x+14)))+(5xx/(2(4x-10)*2*5(x+14)))+(-(1*2(4x-10)*2)/(2(4x-10)*2*5(x+14)))=0


We calculate terms in parentheses: +(-5x^2x/(2(4x-10)*2*5(x+14))), so:

-5x^2x/(2(4x-10)*2*5(x+14))

We multiply all the terms by the denominator


-5x^2x

Back to the equation:

+(-5x^2x)



We calculate terms in parentheses: +(5xx/(2(4x-10)*2*5(x+14))), so:

5xx/(2(4x-10)*2*5(x+14))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)



We calculate terms in parentheses: +(-(1*2(4x-10)*2)/(2(4x-10)*2*5(x+14))), so:

-(1*2(4x-10)*2)/(2(4x-10)*2*5(x+14))

We multiply all the terms by the denominator


-(1*2(4x-10)*2)


We calculate terms in parentheses: -(1*2(4x-10)*2), so:

1*2(4x-10)*2

Wy multiply elements

4x(4

Back to the equation:

-(4x(4)


Back to the equation:

+(-(4x4)


We get rid of parentheses

-5x^2x+5xx+(-4x4=0