1/2(3y-5+4y+2)=y

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Solution for 1/2(3y-5+4y+2)=y equation: 



1/2(3y-5+4y+2)=y

We move all terms to the left:

1/2(3y-5+4y+2)-(y)=0



Domain of the equation: 2(3y-5+4y+2)!=0

y∈R



We add all the numbers together, and all the variables

1/2(7y-3)-y=0

We add all the numbers together, and all the variables

-1y+1/2(7y-3)=0

We multiply all the terms by the denominator


-1y*2(7y-3)+1=0

Wy multiply elements

-2y^2(7+1=0

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