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X/5(X+2)=5X+10
We move all terms to the left:
X/5(X+2)-(5X+10)=0
Domain of the equation: 5(X+2)!=0We get rid of parentheses
X∈R
X/5(X+2)-5X-10=0
We multiply all the terms by the denominator
X-5X*5(X+2)-10*5(X+2)=0
Wy multiply elements
-25X^2(X-50X(X+X=0
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