1/2(3m-2)=1/3(2m+1)

Solution for 1/2(3m-2)=1/3(2m+1) equation:

1/2(3m-2)=1/3(2m+1)

We move all terms to the left:

1/2(3m-2)-(1/3(2m+1))=0


Domain of the equation: 2(3m-2)!=0

m∈R



Domain of the equation: 3(2m+1))!=0

m∈R


We calculate fractions


(3m2/(2(3m-2)*3(2m+1)))+(-2m3/(2(3m-2)*3(2m+1)))=0


We calculate terms in parentheses: +(3m2/(2(3m-2)*3(2m+1))), so:

3m2/(2(3m-2)*3(2m+1))

We multiply all the terms by the denominator


3m2

We add all the numbers together, and all the variables

3m^2

Back to the equation:

+(3m^2)



We calculate terms in parentheses: +(-2m3/(2(3m-2)*3(2m+1))), so:

-2m3/(2(3m-2)*3(2m+1))

We multiply all the terms by the denominator


-2m3

We add all the numbers together, and all the variables

-2m^3

We do not support empression: m^3