(3+c)=-2(5c-2)

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Solution for (3+c)=-2(5c-2) equation: 



(3+c)=-2(5c-2)

We move all terms to the left:

(3+c)-(-2(5c-2))=0

We add all the numbers together, and all the variables

(c+3)-(-2(5c-2))=0

We get rid of parentheses

c-(-2(5c-2))+3=0



We calculate terms in parentheses: -(-2(5c-2)), so:

-2(5c-2)

We multiply parentheses

-10c+4

Back to the equation:

-(-10c+4)



We get rid of parentheses

c+10c-4+3=0

We add all the numbers together, and all the variables

11c-1=0

We move all terms containing c to the left, all other terms to the right

11c=1

c=1/11

c=1/11

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