1/2(3-y)+1/4=1/2(3-y)

Solution for 1/2(3-y)+1/4=1/2(3-y) equation:

1/2(3-y)+1/4=1/2(3-y)

We move all terms to the left:

1/2(3-y)+1/4-(1/2(3-y))=0


Domain of the equation: 2(3-y)!=0

y∈R



Domain of the equation: 2(3-y))!=0

y∈R


We add all the numbers together, and all the variables

1/2(-1y+3)-(1/2(-1y+3))+1/4=0

We calculate fractions


(8y(-)/(2(-1y+3)*2(-1y+3))*4)+(-(1*2(-1y+3)*4)/(2(-1y+3)*2(-1y+3))*4)+(4y^2(-)/(2(-1y+3)*2(-1y+3))*4)=0


We calculate terms in parentheses: +(8y(-)/(2(-1y+3)*2(-1y+3))*4), so:

8y(-)/(2(-1y+3)*2(-1y+3))*4

We add all the numbers together, and all the variables

8y0/(2(-1y+3)*2(-1y+3))*4

We multiply all the terms by the denominator


8y0

We add all the numbers together, and all the variables

8y

Back to the equation:

+(8y)



We calculate terms in parentheses: +(-(1*2(-1y+3)*4)/(2(-1y+3)*2(-1y+3))*4), so:

-(1*2(-1y+3)*4)/(2(-1y+3)*2(-1y+3))*4

We multiply all the terms by the denominator


-(1*2(-1y+3)*4)


We calculate terms in parentheses: -(1*2(-1y+3)*4), so:

1*2(-1y+3)*4

Wy multiply elements

8y(-

Back to the equation:

-(8y(-)


We add all the numbers together, and all the variables

-(8y0

Back to the equation:

+(-(8y0)



We calculate terms in parentheses: +(4y^2(-)/(2(-1y+3)*2(-1y+3))*4), so:

4y^2(-)/(2(-1y+3)*2(-1y+3))*4

We add all the numbers together, and all the variables

4y^20/(2(-1y+3)*2(-1y+3))*4

We multiply all the terms by the denominator


4y^20

We do not support eypression: y^20