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(3x-2)/5+(x+3)/2-3/10=x/2
We move all terms to the left:
(3x-2)/5+(x+3)/2-3/10-(x/2)=0
We add all the numbers together, and all the variables
(3x-2)/5+(x+3)/2-(+x/2)-3/10=0
We get rid of parentheses
(3x-2)/5+(x+3)/2-x/2-3/10=0
We calculate fractions
There is no solution for this equation
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