10-5x=3(x-4)-2(x-2)

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Solution for 10-5x=3(x-4)-2(x-2) equation: 



10-5x=3(x-4)-2(x-2)

We move all terms to the left:

10-5x-(3(x-4)-2(x-2))=0



We calculate terms in parentheses: -(3(x-4)-2(x-2)), so:

3(x-4)-2(x-2)

We multiply parentheses

3x-2x-12+4

We add all the numbers together, and all the variables

x-8

Back to the equation:

-(x-8)



We get rid of parentheses

-5x-x+8+10=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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