1/2(2x+1)-2/3(x-2)=1/6

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Solution for 1/2(2x+1)-2/3(x-2)=1/6 equation: 



1/2(2x+1)-2/3(x-2)=1/6

We move all terms to the left:

1/2(2x+1)-2/3(x-2)-(1/6)=0



Domain of the equation: 2(2x+1)!=0

x∈R





Domain of the equation: 3(x-2)!=0

x∈R



We add all the numbers together, and all the variables

1/2(2x+1)-2/3(x-2)-(+1/6)=0

We get rid of parentheses

1/2(2x+1)-2/3(x-2)-1/6=0

We calculate fractions


(18xx/(2(2x+1)*3(x-2)*6)+(-24x2/(2(2x+1)*3(x-2)*6)+(-6x^22/(2(2x+1)*3(x-2)*6)=0



We calculate terms in parentheses: +(18xx/(2(2x+1)*3(x-2)*6)+(-24x2/(2(2x+1)*3(x-2)*6)+(-6x^22/(2(2x+1)*3(x-2)*6), so:

18xx/(2(2x+1)*3(x-2)*6)+(-24x2/(2(2x+1)*3(x-2)*6)+(-6x^22/(2(2x+1)*3(x-2)*6

We do not support expression: x^22

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