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4(3x+5)+4=3(2x+4)
We move all terms to the left:
4(3x+5)+4-(3(2x+4))=0
We multiply parentheses
12x-(3(2x+4))+20+4=0
We calculate terms in parentheses: -(3(2x+4)), so:We add all the numbers together, and all the variables
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
12x-(6x+12)+24=0
We get rid of parentheses
12x-6x-12+24=0
We add all the numbers together, and all the variables
6x+12=0
We move all terms containing x to the left, all other terms to the right
6x=-12
x=-12/6
x=-2
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