1/2(24-20t)+9t=2(5t+1)

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Solution for 1/2(24-20t)+9t=2(5t+1) equation: 



1/2(24-20t)+9t=2(5t+1)

We move all terms to the left:

1/2(24-20t)+9t-(2(5t+1))=0



Domain of the equation: 2(24-20t)!=0

t∈R



We add all the numbers together, and all the variables

1/2(-20t+24)+9t-(2(5t+1))=0

We add all the numbers together, and all the variables

9t+1/2(-20t+24)-(2(5t+1))=0

We multiply all the terms by the denominator


9t*2(-20t+24)-((2(5t+1)))*2(-20t+24)+1=0



We calculate terms in parentheses: -((2(5t+1)))*2(-20t+24), so:

(2(5t+1)))*2(-20t+24

We add all the numbers together, and all the variables

-20t+(2(5t+1)))*2(+24

Back to the equation:

-(-20t+(2(5t+1)))*2(+24)



We add all the numbers together, and all the variables

9t*2(-20t+24)-(-20t+(2(5t+1)))*224+1=0

Wy multiply elements

18t^2(--(-20t+(2(5t+1)))*224+1=0

We use the square of the difference formula

18t^2(+(-20t+(2(5t+1)))*224+1=0

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