-10x(2x-2)-4=-6(3x-8)-4x

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Solution for -10x(2x-2)-4=-6(3x-8)-4x equation: 



-10x(2x-2)-4=-6(3x-8)-4x

We move all terms to the left:

-10x(2x-2)-4-(-6(3x-8)-4x)=0

We multiply parentheses

-20x^2+20x-(-6(3x-8)-4x)-4=0



We calculate terms in parentheses: -(-6(3x-8)-4x), so:

-6(3x-8)-4x

We add all the numbers together, and all the variables

-4x-6(3x-8)

We multiply parentheses

-4x-18x+48

We add all the numbers together, and all the variables

-22x+48

Back to the equation:

-(-22x+48)



We get rid of parentheses

-20x^2+20x+22x-48-4=0

We add all the numbers together, and all the variables

-20x^2+42x-52=0

a = -20; b = 42; c = -52;
Δ = b2-4ac
Δ = 422-4·(-20)·(-52)
Δ = -2396
Delta is less than zero, so there is no solution for the equation

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