1/2(21-3x)=1/2(8-4x)

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Solution for 1/2(21-3x)=1/2(8-4x) equation: 



1/2(21-3x)=1/2(8-4x)

We move all terms to the left:

1/2(21-3x)-(1/2(8-4x))=0



Domain of the equation: 2(21-3x)!=0

x∈R





Domain of the equation: 2(8-4x))!=0

x∈R



We add all the numbers together, and all the variables

1/2(-3x+21)-(1/2(-4x+8))=0

We calculate fractions


(2x(-)/(2(-3x+21)*2(-4x+8)))+(-2x0/(2(-3x+21)*2(-4x+8)))=0



We calculate terms in parentheses: +(2x(-)/(2(-3x+21)*2(-4x+8))), so:

2x(-)/(2(-3x+21)*2(-4x+8))

We add all the numbers together, and all the variables

2x0/(2(-3x+21)*2(-4x+8))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-2x0/(2(-3x+21)*2(-4x+8))), so:

-2x0/(2(-3x+21)*2(-4x+8))

We multiply all the terms by the denominator


-2x0

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)



We get rid of parentheses

2x-2x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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